Half-life

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(Redirected from Half life)
For other uses, see Half-life (disambiguation).

The half-life of a radioactive substance is the time required for half of a sample to undergo radioactive decay. The term also has pharmaceutical and other uses.

More generally, for a quantity subject to exponential decay, the half-life is the time required for the quantity to fall to half of its initial value. (This article is a narrow discussion of half-life. For phenomena where half-life is applied, see "Related topics" below.)

After # of
Half-lives
Percent of quantity
remaining
0 100%
1 50%
2 25%
3 12.5%
4 6.25%
5 3.125%
6 1.5625%
7 0.78125%
... ...
N <math>\frac{100%}{2^N}</math>
... ...

The table at right shows the reduction of the quantity in terms of the number of half-lives elapsed.

Quantities subject to exponential decay are commonly denoted by the symbol N. (This convention suggests a decaying number of discrete items. This interpretation is valid in many, but not all, cases of exponential decay.) If the quantity is denoted by the symbol N, the value of N at a time t is given by the formula:

<math>N(t) = N_0 e^{-\lambda t} \,</math>

where

When t=0, the exponential is equal to 1, and N(t) is equal to <math>N_0</math>. As t approaches infinity, the exponential approaches zero.

In particular, there is a time <math>t_{1/2} \,</math> such that:

<math>N(t_{1/2}) = N_0\cdot\frac{1}{2} </math>

Substituting into the formula above, we have:

<math>N_0\cdot\frac{1}{2} = N_0 e^{-\lambda t_{1/2}} \,</math>
<math>e^{-\lambda t_{1/2}} = \frac{1}{2} \,</math>
<math>- \lambda t_{1/2} = \ln \frac{1}{2} = - \ln{2} \,</math>
<math>t_{1/2} = \frac{\ln 2}{\lambda} \,</math>

Thus the half-life is 69.3% of the mean lifetime.

Decay by two or more processes

A radioactive element may decay via two or more different processes. These processes may have different probabilities of occurring, and thus there is also a different half-life associated with each process.

As an example, for two decay modes, the amount of substance left after time t is given by

<math>N(t) = N_0 e^{-\lambda _1 t} e^{-\lambda _2 t} = N_0 e^{-(\lambda _1 + \lambda _2) t}</math>

In a fashion similar to the previous section, we can calculate the new total half-life <math>T _{1/2} \,</math> and we'll find it to be

<math>T_{1/2} = \frac{\ln 2}{\lambda _1 + \lambda _2} \,</math>

or, in terms of the two half-lives

<math>T_{1/2} = \frac{t _1 t _2}{t _1 + t_2} \,</math>

Where <math>t _1 \,</math> is the half-life of the first process, and <math>t _2 \,</math> is the half life of the second process.

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