Nilpotent matrix
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In mathematics, a nilpotent matrix is an n×n square matrix M such that
- <math>M^q = 0\,</math>
for some positive integer q. Similarly, a nilpotent transformation is a linear transformation L with <math>L^q = 0</math> for some integer q.
These are special cases of a more general concept of nilpotence that applies not only to matrices and linear transformations but to members of rings.
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Examples
For example, a matrix of the following form:
- <math>
\begin{bmatrix} 0 & 1 & 0 & 0\\ 0 & 0 & 1 & 0\\ 0 & 0 & 0 & 1\\ 0 & 0 & 0 & 0 \end{bmatrix} </math>
This is an example of a 4×4 nilpotent matrix. Notice the non-zero superdiagonal. The characteristic feature of this matrix is:
- <math>
N^2 = \begin{bmatrix}
0 & 0 & 1 & 0\\
0 & 0 & 0 & 1\\
0 & 0 & 0 & 0\\
0 & 0 & 0 & 0
\end{bmatrix}
- \
N^3 = \begin{bmatrix}
0 & 0 & 0 & 1\\
0 & 0 & 0 & 0\\
0 & 0 & 0 & 0\\
0 & 0 & 0 & 0
\end{bmatrix}
- \
N^4 = \begin{bmatrix}
0 & 0 & 0 & 0\\
0 & 0 & 0 & 0\\
0 & 0 & 0 & 0\\
0 & 0 & 0 & 0
\end{bmatrix}.
</math>
The super-diagonal keeps 'shifting' diagonally up, until one gets the null matrix.
The corresponding nilpotent transformation L : R4 → R4 is defined by:
- <math> L(x_1,x_2,x_3,x_4) = (x_2,x_3,x_4,0). \, </math>
There is a classification theorem showing that this is typical: a nilpotent matrix is similar to a block matrix, with diagonal square blocks generalising this type, and other blocks zero.
Properties
Let M be an n×n nilpotent matrix.
- The smallest integer q such that Mq = 0 is smaller than or equal to n.
- The eigenvalues of M are all zero. In fact, a matrix is nilpotent if and only if its eigenvalues are all zero.
- The characteristic polynomial of M is λn.
- The determinant and trace of M are both zero.
- Every strictly upper triangular matrix or strictly lower triangular matrix is nilpotent.
Classification theorem
The above example is typical, as the following result shows. Every nilpotent matrix is similar to a block diagonal matrix
- <math> \begin{bmatrix}
N_1 & 0 & 0 & \ldots & 0 \\ 0 & N_2 & 0 & \ldots & 0 \\ 0 & 0 & N_3 & \ldots & 0 \\ \vdots & \vdots & \vdots & \ddots & \vdots \\ 0 & 0 & 0 & \ldots & N_k
\end{bmatrix} </math> where the blocks <math>N_i</math> have ones on the superdiagonal and zeros everywhere else:
- <math> N_i = \begin{bmatrix}
0 & 1 & 0 & \ldots & 0 & 0 \\ 0 & 0 & 1 & \ldots & 0 & 0 \\ \vdots & \vdots & \vdots & \ddots & \vdots & \vdots \\ 0 & 0 & 0 & \ldots & 1 & 0 \\ 0 & 0 & 0 & \ldots & 0 & 1 \\ 0 & 0 & 0 & \ldots & 0 & 0
\end{bmatrix}. </math>
This fact follows from the Jordan decomposition theorem, together with the result that every matrix similar to a nilpotent matrix is also nilpotent.
Flag of subspaces
A nilpotent transformation L on Rn naturally determines a flag of subspaces
- <math> \{0\} \subset \ker L \subset \ker L^2 \subset \ldots \subset \ker L^{q-1} \subset \ker L^q = U </math>
and a signature
- <math> 0 = n_0 < n_1 < n_2 < \ldots < q_{k-1} < q_k = n,\qquad n_i = \dim \ker N^i. </math>
The signature characterizes L up to a linear transformation. Furthermore, it satisfies the inequalities
- <math> n_{j+1} - n_j \leq n_j - n_{j-1}, \qquad \mbox{for all } j = 1,\ldots,q-1. </math>
Conversely, any sequence of natural numbers satisfying these inequalities is the signature of a nilpotent transformation.



